| ⇦ |
| ⇨ |
The depth at which the effective value of acceleration due to gravity is g/4 is (R=Radius of earth)
Options
(a) R
(b) 3R/4
(c) R/2
(d) R/4
Correct Answer:
3R/4
Explanation:
The effect of depth of acceleration due to gravity is g’=g(1-d/R)
Given, g’=g/4
g/4=g(1-d/R)
(g/4)/g=(1-d/R)
1/4=1-d/R ⇒d/R=1-1/4 ⇒3/4
d=3R/4
Related Questions: - The nuclear fusion reaction between deutrium and tritium takes place
- At absolute temperature, the kinetic energy of the molecules
- Two racing cars of masses m₁ and m₂ are moving in circles of radii
- Function of a rectifier is
- Which of the following will be σ if Y=2.4 η?
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The nuclear fusion reaction between deutrium and tritium takes place
- At absolute temperature, the kinetic energy of the molecules
- Two racing cars of masses m₁ and m₂ are moving in circles of radii
- Function of a rectifier is
- Which of the following will be σ if Y=2.4 η?
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply