⇦ | ⇨ |
The current through an inductor changes from 3 A to 2 A is 1 m/s. If induced e.m.f. in inductor is 5V then L is
Options
(a) 5×10⁻² H
(b) 5×10⁻³ H
(c) 2.5×10⁻³ H
(d) None of these
Correct Answer:
5×10⁻³ H
Explanation:
– L (di / dt) = ε ⇒ L × [(3A – 2A) / (i × 10⁻³s)] = 5 V
Therefore, L = 5 × 10⁻³ H
Related Questions: - The transverse nature of electromagnetic waves is proved by which of the following?
- Copper and carbon wires are connected in series and the combined resistor is kept
- A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum
- A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
- If alternating source of primary coil on transformer is replaced by a Laclanche cell
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The transverse nature of electromagnetic waves is proved by which of the following?
- Copper and carbon wires are connected in series and the combined resistor is kept
- A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum
- A common emitter amplifier gives an output of 3 V for an input of 0.01 V.
- If alternating source of primary coil on transformer is replaced by a Laclanche cell
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply