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The current through an inductor changes from 3 A to 2 A is 1 m/s. If induced e.m.f. in inductor is 5V then L is
Options
(a) 5×10⁻² H
(b) 5×10⁻³ H
(c) 2.5×10⁻³ H
(d) None of these
Correct Answer:
5×10⁻³ H
Explanation:
– L (di / dt) = ε ⇒ L × [(3A – 2A) / (i × 10⁻³s)] = 5 V
Therefore, L = 5 × 10⁻³ H
Related Questions: - Suppose for some reasons, radius of earth were to shrink by 1% of present value,
- The effective length of magnet is 31.4 cm and its pole strength is 0.8Am.
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Suppose for some reasons, radius of earth were to shrink by 1% of present value,
- The effective length of magnet is 31.4 cm and its pole strength is 0.8Am.
- Two beams of light having intensities I and 4I interfere to produce a fringe pattern
- The moon’s radius is 1/ 4 that of the earth and its mass is 1 / 80 times that of the earth
- If R is the radius of earth, the height at which the weight of a body 1/4 of its weight
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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