| ⇦ | 
| ⇨ |
The current through an inductor changes from 3 A to 2 A is 1 m/s. If induced e.m.f. in inductor is 5V then L is
Options
(a) 5×10⁻² H
(b) 5×10⁻³ H
(c) 2.5×10⁻³ H
(d) None of these
Correct Answer:
5×10⁻³ H
Explanation:
– L (di / dt) = ε ⇒ L × [(3A – 2A) / (i × 10⁻³s)] = 5 V
Therefore, L = 5 × 10⁻³ H
Related Questions: - A certain mass of Hydrogen is changed to Helium by the process of fusion
- Coherent sources are those sources for which
- Two 220V – 100W bulbs are connected first in series and then in parallel.
- Assuming the sun to have a spherical outer surface of radius r
- A liquid boils when its vapour pressure equals
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A certain mass of Hydrogen is changed to Helium by the process of fusion
- Coherent sources are those sources for which
- Two 220V – 100W bulbs are connected first in series and then in parallel.
- Assuming the sun to have a spherical outer surface of radius r
- A liquid boils when its vapour pressure equals
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply