| ⇦ | 
| ⇨ |
The correct order of the decreasing ionic radii among the following isoelectronic species are :
Options
(a) Ca²⁺ > K⁺ > S²⁻ > Cl⁻
(b) Cl⁻ > S²⁻ >Ca²⁺ > K⁺
(c) S²⁻ > Cl⁻ >K⁺ >Ca²⁺
(d) K⁺ > Ca²⁺ > Cl⁻ > S²⁻
Correct Answer:
S²⁻ > Cl⁻ >K⁺ >Ca²⁺
Explanation:
Among the isoelectronic species, size increases with the increase in negative charge. Thus S has the highest negative charge and hence largest in size followed by Cl, K and Ca
Related Questions: - Portland cement contains the following amount of CaO
- If the ratio of the rates of diffusion of two gases A and B is 4 : 1. Then the ratio
- Which of the following has sp²-hybridisation
- The hydrolysis product of CH₃COCH₃ + CH₃MgBr is
- Hexoses and pentoses are
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Classification of Elements and Periodicity
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Portland cement contains the following amount of CaO
- If the ratio of the rates of diffusion of two gases A and B is 4 : 1. Then the ratio
- Which of the following has sp²-hybridisation
- The hydrolysis product of CH₃COCH₃ + CH₃MgBr is
- Hexoses and pentoses are
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Classification of Elements and Periodicity (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply