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The correct order in which the O–O bond length increases in the following is
Options
(a) H₂O₂ < O₂ < O₃
(b) O₃ < H₂O₂ < O₂
(c) O₂ < O₃ < H₂O₂
(d) O₂ < H₂O₂ < O₃
Correct Answer:
O₂ < O₃ < H₂O₂
Explanation:
Bond length of O–O in O₂ = 1.21 Å
Bond length of O–O in O₃ = 1.278 Å
Bond length of O–O in H₂O₂ = 1.49 Å
Therefore correct order of O–O bond length is O₂ < O₃ < H₂O₂
Related Questions: - Bond angle in H₂O₂ is
- The oxyacid of phosphorus, in which phosphorus has the lowest oxidation state, is
- According to Bohr’s theory, the angular momentum of electron in 5th orbit is
- If a given sample of water contains 0.06 g of Ca²⁺ ion per kg, calculate
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Bond angle in H₂O₂ is
- The oxyacid of phosphorus, in which phosphorus has the lowest oxidation state, is
- According to Bohr’s theory, the angular momentum of electron in 5th orbit is
- If a given sample of water contains 0.06 g of Ca²⁺ ion per kg, calculate
- Which one of the following statements about transition elements is incorrect
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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