⇦ | ⇨ |
The correct bond order in the following species is
Options
(a) O₂²⁺ < O₂⁻ < O₂⁺
(b) O₂⁺ < O₂⁻ < O₂²⁺
(c) O₂⁻ < O₂⁺ < O₂²⁺
(d) O₂²⁺ < O₂⁺ < O₂⁻
Correct Answer:
O₂⁻ < O₂⁺ < O₂²⁺
Explanation:
O₂⁺ ion -Total number of electrons (16-1)=15.
Electronic configuration σ1s² < σ*1s² < σ2s² < σ*2s² < σ2p²(x) < π2p²(y)=π2p²(z)< π*2p¹(y)
Bond order =N(b)-N(a)/2 = 10-5/2 = 5/2 =2 1/2 O⁻₂ (super oxide ion): Total number of electrons (16+1)=17
Electronic configuration σ1s² < σ*1s² < σ2s² < σ*2s² < σ2p²(x) < π2p²(y)=π2p²(z)< π*2p² (y)=π*2p¹(z)
Bond order =N(b)-N(a)/2 = 10-7/2 = 3/2 =1 1/2
O₂⁺² ion :Total number of electrons (16-2)=14.
Electronic configuration σ1s² < σ*1s² < σ2s² < σ*2s² < σ2p²(x) < π2p²(y)=π2p²(z)
Bond order =N(b)-N(a)/2 = 10-4/2 = 6/2 =3
So bond order :O⁻₂ <O₂⁺<O₂²⁺
Related Questions: - The equivalent weight of phosphoric acid(H₃PO₄) in the reaction
- Maximum number of electrons in a subshell with l=3 and n=4 is
- Rate determining step in nitration of bezene is
- With oxalic acid, glycerol at 530K gives
- Which of the following hydrides is electron deficient molecule?
Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The equivalent weight of phosphoric acid(H₃PO₄) in the reaction
- Maximum number of electrons in a subshell with l=3 and n=4 is
- Rate determining step in nitration of bezene is
- With oxalic acid, glycerol at 530K gives
- Which of the following hydrides is electron deficient molecule?
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply