The correct bond order in the following species is

The Correct Bond Order In The Following Species Is Chemistry Question

The correct bond order in the following species is

Options

(a) O₂²⁺ < O₂⁻ < O₂⁺
(b) O₂⁺ < O₂⁻ < O₂²⁺
(c) O₂⁻ < O₂⁺ < O₂²⁺
(d) O₂²⁺ < O₂⁺ < O₂⁻

Correct Answer:

O₂⁻ < O₂⁺ < O₂²⁺

Explanation:

O₂⁺ ion -Total number of electrons (16-1)=15.

Electronic configuration σ1s² < σ*1s² < σ2s² < σ*2s² < σ2p²(x) < π2p²(y)=π2p²(z)< π*2p¹(y)

Bond order =N(b)-N(a)/2 = 10-5/2 = 5/2 =2 1/2 O⁻₂ (super oxide ion): Total number of electrons (16+1)=17

Electronic configuration σ1s² < σ*1s² < σ2s² < σ*2s² < σ2p²(x) < π2p²(y)=π2p²(z)< π*2p² (y)=π*2p¹(z)

Bond order =N(b)-N(a)/2 = 10-7/2 = 3/2 =1 1/2

O₂⁺² ion :Total number of electrons (16-2)=14.

Electronic configuration σ1s² < σ*1s² < σ2s² < σ*2s² < σ2p²(x) < π2p²(y)=π2p²(z)

Bond order =N(b)-N(a)/2 = 10-4/2 = 6/2 =3

So bond order :O⁻₂ <O₂⁺<O₂²⁺

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Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)

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