| ⇦ | 
| ⇨ |
The condition for obtaining secondary maxima in the diffraction pattern due to single slit is
Options
(a) a sin θ=nλ/2
(b) a sin θ=(2n-1)λ/2
(c) a sin θ=nλ
(d) a sin θ=(2n-1)λ
Correct Answer:
a sin θ=(2n-1)λ/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- A person holding a rifle (mass of person and rifle together is 100 kg) stands on a smooth
- If a body is rolling on the surface, its total energy will be
- A compass needle which is allowed to move in a horizontal plane
- The Kα X-ray of molybdenum has a wavelength of 71×10⁻¹² m. If the energy of a molybdenum
- If in a nuclear fusion process, the masses of the fusing nuclei be m₁ and m₂
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply