| ⇦ | 
| ⇨ |
The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV. If two deutrons are fused to form one ₂⁴He then the energy released is
Options
(a) 30.2 MeV
(b) 25.8 MeV
(c) 23.6 MeV
(d) 19.2 MeV
Correct Answer:
23.6 MeV
Explanation:
₁H² + ₁H² → ₂He⁴ + energy
.·. Energy released = B.E or ₂He⁴ – 2(B.E. of ₁H²)
= 28 – 2(2.2) = 28 – 4.4 = 23.6 Mev
Related Questions: - If a wire is stretched to four times its length, then the specific resistance
- The force F acting on a particle of mass m is indicated by the force-time graph
- Two spherical bodies of mass M and 5 M and radii R and 2 R released in free space
- In an orbital motion, the angular momentum vector is
- Which of the following does not increase regularly?
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a wire is stretched to four times its length, then the specific resistance
- The force F acting on a particle of mass m is indicated by the force-time graph
- Two spherical bodies of mass M and 5 M and radii R and 2 R released in free space
- In an orbital motion, the angular momentum vector is
- Which of the following does not increase regularly?
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply