| ⇦ |
| ⇨ |
The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV. If two deutrons are fused to form one ₂⁴He then the energy released is
Options
(a) 30.2 MeV
(b) 25.8 MeV
(c) 23.6 MeV
(d) 19.2 MeV
Correct Answer:
23.6 MeV
Explanation:
₁H² + ₁H² → ₂He⁴ + energy
.·. Energy released = B.E or ₂He⁴ – 2(B.E. of ₁H²)
= 28 – 2(2.2) = 28 – 4.4 = 23.6 Mev
Related Questions: - The dimensional formula of Plancks’s constant and angular momentum are
- A thin film of soap solution (n=1.4) lies on the top of a glass plate (n=1.5).
- If the radioactive dacay constant of radium is 1.07 x 10⁻⁴ year⁻¹, then its half-life
- The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one
- A polarised light of intensity I₀ is passed through another polariser whose pass axis
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The dimensional formula of Plancks’s constant and angular momentum are
- A thin film of soap solution (n=1.4) lies on the top of a glass plate (n=1.5).
- If the radioactive dacay constant of radium is 1.07 x 10⁻⁴ year⁻¹, then its half-life
- The displacement ‘x’ (in meter) of a particle of mass ‘m’ (in kg) moving in one
- A polarised light of intensity I₀ is passed through another polariser whose pass axis
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply