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The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV. If two deutrons are fused to form one ₂⁴He then the energy released is
Options
(a) 30.2 MeV
(b) 25.8 MeV
(c) 23.6 MeV
(d) 19.2 MeV
Correct Answer:
23.6 MeV
Explanation:
₁H² + ₁H² → ₂He⁴ + energy
.·. Energy released = B.E or ₂He⁴ – 2(B.E. of ₁H²)
= 28 – 2(2.2) = 28 – 4.4 = 23.6 Mev
Related Questions: - An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus.
- which of the following statement is false for the properties of electromagnetic waves?
- The radius of curvature of the convex face of a plano-convex lens is 12 cm
- A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude
- Two identical charges repel each other with a force equal to 10 mgwt they are 0.6 m
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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