The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.

⇦

⇨

The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV. If two deutrons are fused to form one ₂⁴He then the energy released is

Options

(a) 30.2 MeV
(b) 25.8 MeV
(c) 23.6 MeV
(d) 19.2 MeV

Correct Answer:

23.6 MeV

Explanation:

₁H² + ₁H² → ₂He⁴ + energy

.·. Energy released = B.E or ₂He⁴ – 2(B.E. of ₁H²)

= 28 – 2(2.2) = 28 – 4.4 = 23.6 Mev

Related Questions:

1. A wind with speed 40 m/s blows parallel to the roof of a house. The area of the roof
2. One-fourth length of a spring of force constant K is cut away. The force constant
3. In a parallel plate capacitor of capacitance C, a metal sheet is inserted
4. The total energy of an electron in the first excited state of hydrogen atom
5. The phenomenon of radioactivity

Topics: Atoms and Nuclei (136)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends