⇦ | ⇨ |
The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV. If two deutrons are fused to form one ₂⁴He then the energy released is
Options
(a) 30.2 MeV
(b) 25.8 MeV
(c) 23.6 MeV
(d) 19.2 MeV
Correct Answer:
23.6 MeV
Explanation:
₁H² + ₁H² → ₂He⁴ + energy
.·. Energy released = B.E or ₂He⁴ – 2(B.E. of ₁H²)
= 28 – 2(2.2) = 28 – 4.4 = 23.6 Mev
Related Questions: - A thin wire of length L and mass M is bent to form a semicircle.
- The surface tension of a liquid is 5 newton per metre. If a film
- The equivalent resistance of two resistors connected in series is 6 Ω
- A wire elongates by l mm when a load W is hanged from it. If the wire goes over
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin wire of length L and mass M is bent to form a semicircle.
- The surface tension of a liquid is 5 newton per metre. If a film
- The equivalent resistance of two resistors connected in series is 6 Ω
- A wire elongates by l mm when a load W is hanged from it. If the wire goes over
- A particle of mass 100g tied to a string is rotated along a circle of radius 0.5 m
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply