| ⇦ |
| ⇨ |
The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm². The force required to double its length will be
Options
(a) 2×10¹² N
(b) 2×10¹¹ N
(c) 2×10¹⁰ N
(d) 2×10⁶ N
Correct Answer:
2×10⁶ N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The radius of curvature of a convave mirror is 24 cm and the imager is magnified
- Reactance of a capacitor of capacitance C µF for A.C freqency (400 / π) Hz is 25 ohm
- Monochromatic light of frequency 6.0 x 10¹⁴ Hz is produced by a laser. The power emitted
- Two identical capacitors are first connected in series and then in parallel.
- Two thin lenses when placed in contact, then the power of combination is +10 D.
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The radius of curvature of a convave mirror is 24 cm and the imager is magnified
- Reactance of a capacitor of capacitance C µF for A.C freqency (400 / π) Hz is 25 ohm
- Monochromatic light of frequency 6.0 x 10¹⁴ Hz is produced by a laser. The power emitted
- Two identical capacitors are first connected in series and then in parallel.
- Two thin lenses when placed in contact, then the power of combination is +10 D.
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply