| ⇦ | 
| ⇨ |
The angular speed of earth, so that the object on equator may appear weightless is(g = 10 m/s², radius of earth=6400 km)
Options
(a) 1.25 x 10⁻³ rad/s
(b) 1.56 x 10⁻³ rad/s
(c) 1.25 x 10⁻1 rad/s
(d) 1.56 rad/s
Correct Answer:
1.25 x 10⁻³ rad/s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The output of an AND gate is connected to both the inputs of a NOR gate,
- An engine pumps water continuously through a hose. Water leaves the hose
- A mass m moving horizontally (along the x-axis) with velocity v collides and sticks
- A ball is projected upwards from the foot of a tower. The ball crosses the top
- Two wheels having radii in the ratio 1:3 are connected by a common belt
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The output of an AND gate is connected to both the inputs of a NOR gate,
- An engine pumps water continuously through a hose. Water leaves the hose
- A mass m moving horizontally (along the x-axis) with velocity v collides and sticks
- A ball is projected upwards from the foot of a tower. The ball crosses the top
- Two wheels having radii in the ratio 1:3 are connected by a common belt
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Solution:
ω=√(g/R)=√(10/6400*10^3)=1.25*10^(-3) rad/s