| ⇦ | 
| ⇨ |
The alternating current in a circuit is given by I=50 sin314t. The peak value and frequency of the current are
Options
(a) I₀=25 A and f=100 Hz
(b) I₀=50 A and f=50 Hz
(c) I₀=50 A and f=100 Hz
(d) I₀=25 A and f=50 Hz
Correct Answer:
I₀=50 A and f=50 Hz
Explanation:
From standard equation, we have I = I₀ sin ωt —–(i)
Given, I = 50 sin 31 4t —-(ii)
Comparing equation (i) and (ii), we get I₀ = 50 A, ω = 2πf = 314
⇒ f = 314 / (2 × 3.14) = 50 Hz
Related Questions: - Two point white dots are 1 mm apart on a black paper.
- A particle moves with constant speed v along a circular path of radius r and completes
- The time period of a thin bar magnet in Earth’s magnetic field is T
- A condenser of capacity C is charged to a potential difference of V₁. The plates
- The thermo e.m.f. E in volts of a certain thermocouple is found to vary
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two point white dots are 1 mm apart on a black paper.
- A particle moves with constant speed v along a circular path of radius r and completes
- The time period of a thin bar magnet in Earth’s magnetic field is T
- A condenser of capacity C is charged to a potential difference of V₁. The plates
- The thermo e.m.f. E in volts of a certain thermocouple is found to vary
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply