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The alternating current in a circuit is given by I=50 sin314t. The peak value and frequency of the current are
Options
(a) I₀=25 A and f=100 Hz
(b) I₀=50 A and f=50 Hz
(c) I₀=50 A and f=100 Hz
(d) I₀=25 A and f=50 Hz
Correct Answer:
I₀=50 A and f=50 Hz
Explanation:
From standard equation, we have I = I₀ sin ωt —–(i)
Given, I = 50 sin 31 4t —-(ii)
Comparing equation (i) and (ii), we get I₀ = 50 A, ω = 2πf = 314
⇒ f = 314 / (2 × 3.14) = 50 Hz
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The density of ice is 0.9 g/cc and that of sea water is 1.1 g/cc
- A deutron is bombarded on ₈O¹⁶ nucleus and α-particle is emitted. The product nucleus is
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- The temperature of a metal block is increased from 27⁰C to 84⁰C. The rate of radiated energy
- The pressure at the bottom of a tank containing a liquid does not depend on
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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