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The acceleration due to gravity becomes (g/2) where g=acceleration due to gravity on the surface of the earth at a height equal to
Options
(a) 4R
(b) R/4
(c) 2R
(d) R/2
Correct Answer:
R/4
Explanation:
Acceleration due to gravity g=GM/R² Acceleration due to gravity on the surface of the height is g’ = GM/(R+h)² .·. g/g’ = (GM/R²)/(GM/(R+h)²) = (R+h/R)² = (1+h/R)² g’/g = (1+h/R)⁻² = (1-2h/R), When h<<R (g/2)/g = (1-2h/R) ⇒ 1/2 = (1-2h/R) ⇒ 2h/R = 11/2 ⇒ 2h/R = 1/2 ⇒ h = (1/2)(R/2) = R/4
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In circular coil, when number of turns is doubled and resistance becomes 1/4th
- A Carnot engine takes heat from a reservoir at 627⁰C and rejects heat
- A charged particle (charge q) is moving in a circle of radius R with uniform speed v
- An unpolarised beam of intensity I is incident on a pair of nicols making an angle
- A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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