⇦ | ⇨ |
Strong reducing behaviour of H₃PO₂ is due to
Options
(a) high electron gain enthalpy of phosphorus
(b) high oxidation state of phosphorus
(c) presence of two –OH groups and one P–H bond
(d) presence of one –OH group and two P–H bonds
Correct Answer:
presence of one –OH group and two P–H bonds
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Four successive members of the first row transition elements are listed below
- In the periodic table from left to right in a period,the atomic volume
- The correct order of the decreasing ionic radii among the following isoelectronic
- The anion, (Si₆O₁₈)¹²⁻ is present in
- The compound that gives both iodoform and Fehling’s tests is
Topics: P Block Elements in Group 15
(89)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Four successive members of the first row transition elements are listed below
- In the periodic table from left to right in a period,the atomic volume
- The correct order of the decreasing ionic radii among the following isoelectronic
- The anion, (Si₆O₁₈)¹²⁻ is present in
- The compound that gives both iodoform and Fehling’s tests is
Topics: P Block Elements in Group 15 (89)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply