| ⇦ | 
| ⇨ |
Standard entropies of X₂, Y₂ and XY₃ are 60, 40 and 50 J K⁻¹ mol⁻¹ respectively. For the reaction 1/2X₂ + 3/2Y₂ ⇌ XY₃,ΔH = -30 kJ, to be at equilibrium ,the temperature should be
Options
(a) 750 K
(b) 1000 K
(c) 1250 K
(d) 500 K
Correct Answer:
750 K
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Which of the following is not correct regarding terylene
- When carbon monoxide is passed over solid caustic soda heated to 200▫ C it forms
- Hardest compound of boron is
- Copper pyrite, the chief ore of copper, is
- The species having maximum stability is
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is not correct regarding terylene
- When carbon monoxide is passed over solid caustic soda heated to 200▫ C it forms
- Hardest compound of boron is
- Copper pyrite, the chief ore of copper, is
- The species having maximum stability is
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply