| ⇦ | 
| ⇨ |
Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:
Options
(a) 1
(b) 1.02
(c) 1.04
(d) 0.98
Correct Answer:
1
Explanation:
energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0
Related Questions: - Resistances n, each r Ω, when connected in parallel give an equivalent resistance
- An electric bulb has a rated power of 50W at 100 V. if it used on an a.c. source
- In an LCR series A.C circuit, the voltage across each of the components, L, C and R is 50V
- The voltage of clouds is 4×10⁶ volt with respect to ground. In a lightening
- The density of ice is 0.9 g/cc and that of sea water is 1.1 g/cc
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Resistances n, each r Ω, when connected in parallel give an equivalent resistance
- An electric bulb has a rated power of 50W at 100 V. if it used on an a.c. source
- In an LCR series A.C circuit, the voltage across each of the components, L, C and R is 50V
- The voltage of clouds is 4×10⁶ volt with respect to ground. In a lightening
- The density of ice is 0.9 g/cc and that of sea water is 1.1 g/cc
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply