| ⇦ |
| ⇨ |
Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:
Options
(a) 1
(b) 1.02
(c) 1.04
(d) 0.98
Correct Answer:
1
Explanation:
energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0
Related Questions: - A wire of length 1 m is placed in a uniform magnetic field of 1.5 tesla at an angle
- CO₂ laser uses
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
- A ball rolls off the top of stair way with a horizontal velocity of magnitude 1.8 m/s
- Length of a conductor is 50 cm radius of cross section 0.1 cm and resistivity
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire of length 1 m is placed in a uniform magnetic field of 1.5 tesla at an angle
- CO₂ laser uses
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
- A ball rolls off the top of stair way with a horizontal velocity of magnitude 1.8 m/s
- Length of a conductor is 50 cm radius of cross section 0.1 cm and resistivity
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply