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Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:
Options
(a) 1
(b) 1.02
(c) 1.04
(d) 0.98
Correct Answer:
1
Explanation:
energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0
Related Questions: - An ideal heat engine works between temperature T₁=500 K and T₂=375 K.
- A p-n-p transistor is used in common emitter mode in an amplifier circuit.
- A sample of HCl gas is placed in an electric field of 5 x 10⁴ N/C
- When 4 A current flows for 2 min in an electroplating experiment,
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An ideal heat engine works between temperature T₁=500 K and T₂=375 K.
- A p-n-p transistor is used in common emitter mode in an amplifier circuit.
- A sample of HCl gas is placed in an electric field of 5 x 10⁴ N/C
- When 4 A current flows for 2 min in an electroplating experiment,
- An electric dipole of length 1 cm is placed with the axis making an angle of 30⁰
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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