| ⇦ | 
| ⇨ |
Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:
Options
(a) 1
(b) 1.02
(c) 1.04
(d) 0.98
Correct Answer:
1
Explanation:
energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0
Related Questions: - The control rods used in a nuclear reactor can be made up of
- A string is stretched between fixed points seperated by 75 cm. It is observed
- The displacement of an object attached to a spring and executing simple harmonic
- A body moves with a uniform acceleration a and zero initial velocity
- Two charges placed in air repel each other by a force of 10⁻⁴ N. When oil is
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The control rods used in a nuclear reactor can be made up of
- A string is stretched between fixed points seperated by 75 cm. It is observed
- The displacement of an object attached to a spring and executing simple harmonic
- A body moves with a uniform acceleration a and zero initial velocity
- Two charges placed in air repel each other by a force of 10⁻⁴ N. When oil is
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply