| ⇦ | 
| ⇨ |
Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:
Options
(a) 1
(b) 1.02
(c) 1.04
(d) 0.98
Correct Answer:
1
Explanation:
energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0
Related Questions: - A ball is dropped from a height of 20 cm. Ball rebounds to a height of 10cm
- A body weighs 50 grams in air and 40 grams in water. How much would it weigh in a liquid
- Dimensions [ML⁻¹T⁻¹] are related with
- The tension in a piano wire is 10 N. What should be the tension in the wire to produce
- The average power dissipated in a pure inductor is
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A ball is dropped from a height of 20 cm. Ball rebounds to a height of 10cm
- A body weighs 50 grams in air and 40 grams in water. How much would it weigh in a liquid
- Dimensions [ML⁻¹T⁻¹] are related with
- The tension in a piano wire is 10 N. What should be the tension in the wire to produce
- The average power dissipated in a pure inductor is
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply