| ⇦ |
| ⇨ |
Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:
Options
(a) 1
(b) 1.02
(c) 1.04
(d) 0.98
Correct Answer:
1
Explanation:
energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0
Related Questions: - Two pendulums A and B are oscillating simultaneously with time period
- The rest mass of a body is m1. It moves with a velocity of 0.6c, then its relativistic
- The transition from the state 3 n = 3 to n = 1 in a hydrogen like atom results
- Identify the pair whose dimensions are equal
- If the velocity of charged particle has both perpendicular and parallel components
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two pendulums A and B are oscillating simultaneously with time period
- The rest mass of a body is m1. It moves with a velocity of 0.6c, then its relativistic
- The transition from the state 3 n = 3 to n = 1 in a hydrogen like atom results
- Identify the pair whose dimensions are equal
- If the velocity of charged particle has both perpendicular and parallel components
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply