| ⇦ | 
| ⇨ |
Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:
Options
(a) 1
(b) 1.02
(c) 1.04
(d) 0.98
Correct Answer:
1
Explanation:
energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0
Related Questions: - Which one of the following electrical meter has the smallest resistance?
- If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
- The flux linked with a circuit is given by φ=t³+3t-7. The graph between time
- Which of the following does not increase regularly?
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following electrical meter has the smallest resistance?
- If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
- The flux linked with a circuit is given by φ=t³+3t-7. The graph between time
- Which of the following does not increase regularly?
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply