Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å

Source S Is Producing 10 Photons Per Second Of Wavelength Physics Question

Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:

Options

(a) 1
(b) 1.02
(c) 1.04
(d) 0.98

Correct Answer:

1

Explanation:

energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0

Related Questions:

  1. If sound wave travel from air to water, which of the following remains unchanged?
  2. The electric field part of an electromagnetic wave in a medium is represented by
  3. Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C
  4. Two straight wires each 10cm long are parallel to one another and seperated by 2 cm.
  5. A coil of self-inductance L is connected in series with a bulb B and an AC source

Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*