| ⇦ | 
| ⇨ |
Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å. Another source S₂ is producing 1.02 x 10¹⁵ photons per second of wavelength 5100Å Then, (power of S₂) (power of S₁) is equal to:
Options
(a) 1
(b) 1.02
(c) 1.04
(d) 0.98
Correct Answer:
1
Explanation:
energy emitted/sec by S₁, P₁ = n₁ hc / λ₁
energy emitted/sec by S₂, P₂ = n₂ hc / λ₂
P₂ / P₁ = n₂ / n₁ . λ₁ / λ₂
= 1.02 x 10¹⁵ / 10¹⁵ . 5000 / 5100 = 1.0
Related Questions: - The ratio of amplitude of magnetic field to the amplitude of electric field for
- Two positive ions, each carrying a charge q, are separated by a distance d
- when a magnetic field is applied on a stationary electron, then it
- A bar magnet having a magnetic moment of 2 x 10⁴JT⁻¹ is free to rotate in a horizontal
- A body A experiences perfectly elastic collision with a stationary body B
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of amplitude of magnetic field to the amplitude of electric field for
- Two positive ions, each carrying a charge q, are separated by a distance d
- when a magnetic field is applied on a stationary electron, then it
- A bar magnet having a magnetic moment of 2 x 10⁴JT⁻¹ is free to rotate in a horizontal
- A body A experiences perfectly elastic collision with a stationary body B
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply