| ⇦ | 
| ⇨ |
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
Options
(a) 9.25
(b) 4.75
(c) 3.75
(d) 8.25
Correct Answer:
4.75
Explanation:
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl is a buffer solution.
According to Henderson equation,
The pH of a basic buffer,
pH = 14 -pK(b) – log{C(salt)/C(base)}.
⇒pK(b) = 14-pH-log{C(salt)/C(base)},
⇒ pK(b) = 14-9.25-log{0.1/0.1}.
⇒ pK(b) = 14-9.25 = 4.75.
Therefore pK(b) of NH₄OH = 4.75.
Related Questions: - MnO₂ and H₂O added to Nacl, the greenish-yellow gas liberate is
- Which of the following carbocations will be most stable
- The mass of an object changes from 0.002 g to 0.00025 g in a time period
- The heat of neutralization is the highest in the following case
- Aluminium (III) chloride forms a dimer because aluminium
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- MnO₂ and H₂O added to Nacl, the greenish-yellow gas liberate is
- Which of the following carbocations will be most stable
- The mass of an object changes from 0.002 g to 0.00025 g in a time period
- The heat of neutralization is the highest in the following case
- Aluminium (III) chloride forms a dimer because aluminium
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply