⇦ | ⇨ |
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
Options
(a) 9.25
(b) 4.75
(c) 3.75
(d) 8.25
Correct Answer:
4.75
Explanation:
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl is a buffer solution.
According to Henderson equation,
The pH of a basic buffer,
pH = 14 -pK(b) – log{C(salt)/C(base)}.
⇒pK(b) = 14-pH-log{C(salt)/C(base)},
⇒ pK(b) = 14-9.25-log{0.1/0.1}.
⇒ pK(b) = 14-9.25 = 4.75.
Therefore pK(b) of NH₄OH = 4.75.
Related Questions: - Violet coloured complex obtained in the detection of Sulphur is
- The oxidation number of P in Mg₂P₂O₇ is
- Metallic crystalline solids have
- when a manganous salt is fused with a mixture of KNO₃ and solid NaOH
- In an alkaline medium, glycine predominantly exists in a
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Violet coloured complex obtained in the detection of Sulphur is
- The oxidation number of P in Mg₂P₂O₇ is
- Metallic crystalline solids have
- when a manganous salt is fused with a mixture of KNO₃ and solid NaOH
- In an alkaline medium, glycine predominantly exists in a
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply