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Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
Options
(a) 9.25
(b) 4.75
(c) 3.75
(d) 8.25
Correct Answer:
4.75
Explanation:
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl is a buffer solution.
According to Henderson equation,
The pH of a basic buffer,
pH = 14 -pK(b) – log{C(salt)/C(base)}.
⇒pK(b) = 14-pH-log{C(salt)/C(base)},
⇒ pK(b) = 14-9.25-log{0.1/0.1}.
⇒ pK(b) = 14-9.25 = 4.75.
Therefore pK(b) of NH₄OH = 4.75.
Related Questions: - Ostwald’s dilution law is applicable to only
- Reaction between an acyl halide and the sodium salt of a fatty acid results in
- Maximum bond angle at nitrogen is present in which of the following
- If the enthalpy change for the transition of liquid water to steam
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Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ostwald’s dilution law is applicable to only
- Reaction between an acyl halide and the sodium salt of a fatty acid results in
- Maximum bond angle at nitrogen is present in which of the following
- If the enthalpy change for the transition of liquid water to steam
- Change in enthalpy for reaction,2H₂O₂ → 2H₂O + O₂
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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