| ⇦ | 
| ⇨ |
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
Options
(a) 9.25
(b) 4.75
(c) 3.75
(d) 8.25
Correct Answer:
4.75
Explanation:
Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl is a buffer solution.
According to Henderson equation,
The pH of a basic buffer,
pH = 14 -pK(b) – log{C(salt)/C(base)}.
⇒pK(b) = 14-pH-log{C(salt)/C(base)},
⇒ pK(b) = 14-9.25-log{0.1/0.1}.
⇒ pK(b) = 14-9.25 = 4.75.
Therefore pK(b) of NH₄OH = 4.75.
Related Questions: - Ethyl alcohol exhibits acidic character on reacting with
- Which of the following is not hydrolysed easily
- If the atomic number of an element is 33, it will be placed in the periodic table
- The magnetic moment of Sc³⁺ is
- The constituent of light oil is
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ethyl alcohol exhibits acidic character on reacting with
- Which of the following is not hydrolysed easily
- If the atomic number of an element is 33, it will be placed in the periodic table
- The magnetic moment of Sc³⁺ is
- The constituent of light oil is
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply