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Siver chloride is soluble in methylamine due to the formation of
Options
(a) [Ag(CH₃NH₂)₂]Cl
(b) Ag(CH₃NH₂)Cl
(c) AgOH
(d) Ag + CH₃Cl + NH₄Cl
Correct Answer:
[Ag(CH₃NH₂)₂]Cl
Explanation:
Silver chloride dissolves in methyl amine to form a complex. AgCl + 2CH₃NH₂ → [Ag(NH₂CH₃)₂]Cl (soluble complex)
Related Questions: - The long form of periodic table is based on
- HSO₄⁻ + OH⁻ → SO₄²⁻ + H₂O. which is correct about conjugate acid – base pair
- A molal solution is one that contains one mole of a solute in
- At 25⁰C, the dissociation constant of a base, BOH, is 1.0 ˣ 10⁻¹².
- Which one of the following complexes is not expected to exhibit isomerism
Topics: Coordination Compounds
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The long form of periodic table is based on
- HSO₄⁻ + OH⁻ → SO₄²⁻ + H₂O. which is correct about conjugate acid – base pair
- A molal solution is one that contains one mole of a solute in
- At 25⁰C, the dissociation constant of a base, BOH, is 1.0 ˣ 10⁻¹².
- Which one of the following complexes is not expected to exhibit isomerism
Topics: Coordination Compounds (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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