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Siver chloride is soluble in methylamine due to the formation of
Options
(a) [Ag(CH₃NH₂)₂]Cl
(b) Ag(CH₃NH₂)Cl
(c) AgOH
(d) Ag + CH₃Cl + NH₄Cl
Correct Answer:
[Ag(CH₃NH₂)₂]Cl
Explanation:
Silver chloride dissolves in methyl amine to form a complex. AgCl + 2CH₃NH₂ → [Ag(NH₂CH₃)₂]Cl (soluble complex)
Related Questions: - DDT is prepared by reacting chlorobenzen with
- Which of the following group activates the benzene ring most towards electrophili
- In which of the following compounds manganese has oxidation number equal
- At higher temperature,iodoform reaction is given by
- D(+)-glucose reacts with hydroxyl amine and yields an oxime.
Topics: Coordination Compounds
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- DDT is prepared by reacting chlorobenzen with
- Which of the following group activates the benzene ring most towards electrophili
- In which of the following compounds manganese has oxidation number equal
- At higher temperature,iodoform reaction is given by
- D(+)-glucose reacts with hydroxyl amine and yields an oxime.
Topics: Coordination Compounds (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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