| ⇦ | 
| ⇨ |
Reaction of solid KMnO₄ with conc.H₂SO₄ produces manganese heptoxide (Mn₂O₇) in
Options
(a) solution state
(b) solid state
(c) fine powder
(d) none of these
Correct Answer:
solution state
Explanation:
KMnO₄ on treatment with concentrated H₂SO₄ forms manganese heptoxide via permanganyl sulphate which decomposes explosively on heating. 2KMnO₄ + 3H₂SO₄ → 2KHSO₄ + (MnO₃)₂SO₄ + 2H₂O. (MnO₃)₂SO₄ + H₂O → Mn₂O₇(Red-brown liquid) + H₂SO₄. Mn₂O₇ → 2MnO₂ + 3/2 O₂. Therefore Mn₂O₇ so formed is a red-brown liquid.
Related Questions:
- When the first ionisation energies are plotted against atomic number
- In the gas phase reaction C₂H₂ + H₂ ⇌ C₂H₆, the equilibrium constant
- The incorrect statement among the following is
- Correct order of the stability of group IIA metal carbonates is
- The atomic number of cobalt is 27. The EAN of cobalt in Na₃[Co(NO₂)₄Cl₂] is
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply