Ratio of Cᵥ and Cᵥ of the gas X is 1.4. The number of atoms of the gas X present

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Ratio of Cᵥ and Cᵥ of the gas X is 1.4. The number of atoms of the gas X present in 11.2 litres of it at NTP will be

Options

(a) 6.02 x 10²³
(b) 1.2 x 10²³
(c) 3.01 x 10²³
(d) 2.01 x 10²³

Correct Answer:

6.02 x 10²³

Explanation:

gas is diatomic based on Cₚ and Cᵥ ratio
According to Avogadro’s hypothesis we have come to know that the molar volume of a gas at STP is 22.4 litres
22.4 litre at NTP = 6.02 x 10²³ molecules
11.2 L at NTP = 3.01 x 10²³ molecules
= 3.01 x 10²³ molecules x 2 atoms = 6.02 x 10²³ molecules

Related Questions:

1. Write the IUPAC name of CH₃CH₂COOH
2. Which of the following is diamagnetic
3. Which one of the following is not an aldose
4. Isoprene is used for the preparation of
5. Complex ion is shown by

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

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