⇦ | ⇨ |
Radius of a soap bubble is increased from R to 2R. Work done in this process in terms of surface tension S is
Options
(a) 24 πR²S
(b) 48 πR²S
(c) 12 πR²S
(d) 36 πR²S
Correct Answer:
24 πR²S
Explanation:
Work done = 2 x S x Change in surface area
W = 2 x S x 4π (R₂² – R₁²)
Given: R₂ = 2R, R₁ = R = 8S π (4R² – R²) = 24 πR²S.
Related Questions: - The sum of the magnitudes of two forces acting at a point is 16 N
- Which of the following rods of same material undergoes maximum elongation
- The following four wires are made of the same material. Which of these will have
- A sound absorber attenuates the sound level by 20 dB. The intensity decreases
- Photocells convert
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The sum of the magnitudes of two forces acting at a point is 16 N
- Which of the following rods of same material undergoes maximum elongation
- The following four wires are made of the same material. Which of these will have
- A sound absorber attenuates the sound level by 20 dB. The intensity decreases
- Photocells convert
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply