| ⇦ | 
| ⇨ |
Power dissipated in an LCR series circuit connected to an a.c source of emf ? is
Options
(a) ?ￂﾲ √ [ R² + ( L? – 1 / C?)² ] / R
(b) ?ￂﾲ [ R² + ( L? – 1 / C?)² ] / R
(c) ?ￂﾲR / √ [ R² + ( L? – 1 / C?)² ]
(d) ?ￂﾲR / [ R² + ( L? – 1 / C?)² ]
Correct Answer:
?ￂﾲR / [ R² + ( L? – 1 / C?)² ]
Explanation:
Power dissipated in series LCR;
P = IR = / (Z) R
= ?ￂﾲR / [ R² + ( L? – 1 / C?)² ]
where Z = √ R² + ( L? – 1 / C?)²
is called the impedance of the circuit.
Related Questions: - A wire of one metre length carries a constant current. The wire is bent to form
- A small part of the rim of a fly wheel breaks off while it is rotating at a constant
- If a gymnast, sitting on a rotating stool with his arms outstretched, suddenly
- A particle executing SHM with amplitude of 0.1 m. At a certain instant,
- The e.m.f. of a battery is 2 V and its internal resistance is 0.5 Ω. The maximum
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire of one metre length carries a constant current. The wire is bent to form
- A small part of the rim of a fly wheel breaks off while it is rotating at a constant
- If a gymnast, sitting on a rotating stool with his arms outstretched, suddenly
- A particle executing SHM with amplitude of 0.1 m. At a certain instant,
- The e.m.f. of a battery is 2 V and its internal resistance is 0.5 Ω. The maximum
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply