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Power dissipated in an LCR series circuit connected to an a.c source of emf ? is
Options
(a) ?ᅡᄇ √ [ R² + ( L? – 1 / C?)² ] / R
(b) ?ᅡᄇ [ R² + ( L? – 1 / C?)² ] / R
(c) ?ᅡᄇR / √ [ R² + ( L? – 1 / C?)² ]
(d) ?ᅡᄇR / [ R² + ( L? – 1 / C?)² ]
Correct Answer:
?ᅡᄇR / [ R² + ( L? – 1 / C?)² ]
Explanation:
Power dissipated in series LCR;
P = IR = / (Z) R
= ?ᅡᄇR / [ R² + ( L? – 1 / C?)² ]
where Z = √ R² + ( L? – 1 / C?)²
is called the impedance of the circuit.
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wheel of mass 10 kg has a moment of inertia of 10 kgm² about its own axis
- The energy released in the fission of 1 kg of ₉₂U²³⁵ is (energy per fission = 200 MeV)
- When the angle of incidence is 60° on the surface of a glass slab, it is found
- A parallel beam of light of wavelength λ is incident normally on a narrow slit
- In an A.C circuit of capacitance the current from potential is
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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