| ⇦ | 
| ⇨ |
Point masses m₁ and m₂ are placed at the opposite ends of a rigid rod of length L, and negligible mass. The rod is to be set rotating about an axis perpendicular to it. The position of point P on this rod through which the axis should pass so that the work required to set the rod rotating with angular velocity ω₀ is minimum, is given by
Options
(a) x= m₂/m₁ L
(b) x= m₂L/m₁+m₂
(c) x= m₁L/m₁+m₂
(d) x= m₁/m₂ L
Correct Answer:
x= m₂L/m₁+m₂
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- The electric potential at a point (x,y,z) is given by V = – x²y – xz³ + 4.
- If R is the radius of earth, the height at which the weight of a body 1/4 of its weight
- The oscillation of a body on a smooth horizontal surface is represented by the equation
- A copper disc of radius 0.1 m is rotated about its centre, with 10 revolutions
- Two wires of the same dimensions but resistivities p1 and p2 are connected in series
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply