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Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The manifestation of band structure in solids is due to
- SI unit of permittivity is
- The oscillating frequency of a cyclotron is 10 MHz. If the radius of its Dees is o.5 m,
- A uniform force of (3i + j) newton acfs on a particle of mass 2kg
- Two charges each equal to 2µ C are 0.5m apart. If both of them exist inside vacuum
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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