Periodic time of a satellite revolving above Earth’s surface at a height equal to R,

Periodic Time Of A Satellite Revolving Above Earths Surface At Physics Question

Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)

Options

(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g

Correct Answer:

4√2√R/g

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm².
  2. The ratio of specific charge of an α-particle to that of a proton is
  3. A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 ohm
  4. Ohm’s law is not applicable except to
  5. Which one of the following electrical meter has the smallest resistance?

Topics: Gravitation (63)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*