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Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a common emitter transistor amplifier, the voltage gain is
- A body weighs 50 grams in air and 40 grams in water. How much would it weigh in a liquid
- Two parallel long wires carry currents i₁ and i₂ with i₁ > i₂ .
- The direction of magnetic line of force of a bar magnet is
- Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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