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Periodic time of a satellite revolving above Earth’s surface at a height equal to R, radius of Earth is (g=acceleration due to gravity at Earth’s surface)
Options
(a) 2π√2R/g
(b) 4√2√R/g
(c) 2π√R/g
(d) 8π√R/g
Correct Answer:
4√2√R/g
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s,
- An electric dipole of dipole moment p is placed in a uniform external electric field
- A transistor is working in common emitter mode. Its amplification factor is 80
- A particle of masses m is thrown upwards from the surface of the earth, with a velocity u
- Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 μC each.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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