If the equivalent weight of an element is 32, then the percentage of oxygen
If the equivalent weight of an element is 32, then the percentage of oxygen in its oxide is
Options
(a) 16 (b) 40 (c) 32 (d) 20
Correct Answer:
20
Explanation:
Equi. Wt […]
If the equivalent weight of an element is 32, then the percentage of oxygen in its oxide is
Options
(a) 16 (b) 40 (c) 32 (d) 20
Correct Answer:
20
Explanation:
Equi. Wt […]
The total number of atomic orbitals in fourth energy level of an atom is :
Options
(a) 8 (b) 16 (c) 32 (d) 4
Correct Answer:
16
Explanation:
Total number of atomic orbits […]
The density of air is 0.001293 g/cc at STP. Its vapour density is
Options
(a) 0.001293 (b) 8.2786 (c) 14.49 (d) 6.2706
Correct Answer:
14.49
Explanation:
At STP, 22.4 litres of gas is equal […]
Maximum number of electrons in a subshell with l=3 and n=4 is
Options
(a) 14 (b) 16 (c) 10 (d) 12
Correct Answer:
14
Explanation:
n = main energy level / = subshell […]
For azimuthal quantum number l= 3,the maximum number of electrons will be
Options
(a) 2 (b) 6 (c) 0 (d) 14
Correct Answer:
14
Explanation:
l= 3 means f-subshell. Maximum no. of electrons […]
Boron has two stable isotopes, ¹°B(19%) and ¹¹B(81%). Average atomic weight for boron in the periodic table is
Options
(a) 10.8 (b) 10.2 (c) 11.2 (d) 10
Correct Answer:
10.8
Explanation:
Avg Atomic […]
1.520 g of hydroxide of a metal on ignition gave 0.995 g of oxide. The equivalent weight of metal is
Options
(a) 1.52 (b) 0.995 (c) 190 (d) 9
Correct Answer:
9
Explanation:
One […]
If principal quantum number n=4, the total number of orbitals having l=3 is
Options
(a) 3 (b) 7 (c) 5 (d) 9
Correct Answer:
7
Explanation:
For n= 4, /= 3 (f-subshell) no. […]
At S.T.P the density of CCl₄ vapours in g/L will be nearest to
Options
(a) 6.87 (b) 3.42 (c) 10.26 (d) 4.57
Correct Answer:
6.87
Explanation:
Molecular Weight of CCl₄ = 35.5 + […]
Maximum number of H-bonds in one molecule of water is
Options
(a) 1 (b) 2 (c) 3 (d) 4
Correct Answer:
4
Explanation:
No explanation available. Be the first to write the explanation […]
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