| ⇦ | 
| ⇨ |
Oxidation state of sulphur in S₈, H₂S and S₂F₂ is
Options
(a) 0, -2, -1
(b) 0, 2, -1
(c) 1, -2, 1
(d) 0, -2, 1
Correct Answer:
0, -2, 1
Explanation:
Oxidation state of Sulphur in S₈ = 0,
Sulphur in H₂S = 2+x = 0, x = -2,
Sulphur in S₂F₂ = 2x + 2(-1) = 0,
2x – 2 = 0, x = 1.
Related Questions: - A particular solid is very hard and has a very high melting point. In solid
- All Cu(II) halides are known except the iodide. The reason for it is that
- When two atoms of chlorine combine to form one molecule of chlorine gas
- Reaction of nitrous acid with aliphatic primary amine will give
- Which of the following compounds gives benzoic acid on hydrolysis
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particular solid is very hard and has a very high melting point. In solid
- All Cu(II) halides are known except the iodide. The reason for it is that
- When two atoms of chlorine combine to form one molecule of chlorine gas
- Reaction of nitrous acid with aliphatic primary amine will give
- Which of the following compounds gives benzoic acid on hydrolysis
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply