| ⇦ | 
| ⇨ |
Oxidation state of sulphur in S₈, H₂S and S₂F₂ is
Options
(a) 0, -2, -1
(b) 0, 2, -1
(c) 1, -2, 1
(d) 0, -2, 1
Correct Answer:
0, -2, 1
Explanation:
Oxidation state of Sulphur in S₈ = 0,
Sulphur in H₂S = 2+x = 0, x = -2,
Sulphur in S₂F₂ = 2x + 2(-1) = 0,
2x – 2 = 0, x = 1.
Related Questions: - For isothermal change in the case of an ideal gas
- 1,1,2,2-tetrabromoethane on treatment with Zn dust yields an
- Which of the following statements about amorphous solids is incorrect
- Reaction between an acyl halide and the sodium salt of a fatty acid results in
- General electronic configuration of lanthanides is
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For isothermal change in the case of an ideal gas
- 1,1,2,2-tetrabromoethane on treatment with Zn dust yields an
- Which of the following statements about amorphous solids is incorrect
- Reaction between an acyl halide and the sodium salt of a fatty acid results in
- General electronic configuration of lanthanides is
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply