| ⇦ | 
| ⇨ |
Oxidation state of sulphur in S₈, H₂S and S₂F₂ is
Options
(a) 0, -2, -1
(b) 0, 2, -1
(c) 1, -2, 1
(d) 0, -2, 1
Correct Answer:
0, -2, 1
Explanation:
Oxidation state of Sulphur in S₈ = 0,
Sulphur in H₂S = 2+x = 0, x = -2,
Sulphur in S₂F₂ = 2x + 2(-1) = 0,
2x – 2 = 0, x = 1.
Related Questions: - Aqueous solutions of hydrogen sulphide and sulphur dioxide when mixed together
- Specific conductance of 0.1 M sodium chloride solution is 1.06 ˣ 10⁻²
- Ester and acetamide are distinguished dy
- If in a container no mass and no heat exchange occurs then it constitutes a
- Dynamite contains
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Aqueous solutions of hydrogen sulphide and sulphur dioxide when mixed together
- Specific conductance of 0.1 M sodium chloride solution is 1.06 ˣ 10⁻²
- Ester and acetamide are distinguished dy
- If in a container no mass and no heat exchange occurs then it constitutes a
- Dynamite contains
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply