| ⇦ |
| ⇨ |
Oxidation state of sulphur in S₈, H₂S and S₂F₂ is
Options
(a) 0, -2, -1
(b) 0, 2, -1
(c) 1, -2, 1
(d) 0, -2, 1
Correct Answer:
0, -2, 1
Explanation:
Oxidation state of Sulphur in S₈ = 0,
Sulphur in H₂S = 2+x = 0, x = -2,
Sulphur in S₂F₂ = 2x + 2(-1) = 0,
2x – 2 = 0, x = 1.
Related Questions: - In which of the folowing pair both the species have sp³ hybridization?
- Which one of the following is antimalarial drug
- Which one of the following does not correctly represent the correct order
- Hofmann bromamide reaction is used to prepare
- Measurement of the dry gas from the volume of moist gas is based on
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In which of the folowing pair both the species have sp³ hybridization?
- Which one of the following is antimalarial drug
- Which one of the following does not correctly represent the correct order
- Hofmann bromamide reaction is used to prepare
- Measurement of the dry gas from the volume of moist gas is based on
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply