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Oxidation state of sulphur in S₈, H₂S and S₂F₂ is
Options
(a) 0, -2, -1
(b) 0, 2, -1
(c) 1, -2, 1
(d) 0, -2, 1
Correct Answer:
0, -2, 1
Explanation:
Oxidation state of Sulphur in S₈ = 0,
Sulphur in H₂S = 2+x = 0, x = -2,
Sulphur in S₂F₂ = 2x + 2(-1) = 0,
2x – 2 = 0, x = 1.
Related Questions: - Who modified Bohr’s theory by introducing elliptical orbits for electron path
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Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Who modified Bohr’s theory by introducing elliptical orbits for electron path
- Which one of the elements has the highest ionisation energy?
- The covalent bond length is the shortest in which one of the following bonds
- The hybridised state of N in R₂NH is
- For which one of the following sets of four quantum numbers, an electron will have
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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