| ⇦ | 
| ⇨ |
Oxidation state of sulphur in S₈, H₂S and S₂F₂ is
Options
(a) 0, -2, -1
(b) 0, 2, -1
(c) 1, -2, 1
(d) 0, -2, 1
Correct Answer:
0, -2, 1
Explanation:
Oxidation state of Sulphur in S₈ = 0,
Sulphur in H₂S = 2+x = 0, x = -2,
Sulphur in S₂F₂ = 2x + 2(-1) = 0,
2x – 2 = 0, x = 1.
Related Questions: - The oxidation states of Mn in MnSO₄,MnO₂,K₂MnO₄ and KMnO₄ are respectively
- The electrophile in the nitration of benzene is
- Water is oxidised to oxygen by
- The extra amount of energy, which the molecules of the reactants have to absorb
- The oxyacid of phosphorus, in which phosphorus has the lowest oxidation state, is
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The oxidation states of Mn in MnSO₄,MnO₂,K₂MnO₄ and KMnO₄ are respectively
- The electrophile in the nitration of benzene is
- Water is oxidised to oxygen by
- The extra amount of energy, which the molecules of the reactants have to absorb
- The oxyacid of phosphorus, in which phosphorus has the lowest oxidation state, is
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply