| ⇦ |
| ⇨ |
Oxidation state of sulphur in S₈, H₂S and S₂F₂ is
Options
(a) 0, -2, -1
(b) 0, 2, -1
(c) 1, -2, 1
(d) 0, -2, 1
Correct Answer:
0, -2, 1
Explanation:
Oxidation state of Sulphur in S₈ = 0,
Sulphur in H₂S = 2+x = 0, x = -2,
Sulphur in S₂F₂ = 2x + 2(-1) = 0,
2x – 2 = 0, x = 1.
Related Questions: - Primary,secondary and tertiary amines may be separated by using
- 10g of hydrogen and 64g of oxygen were filled in a steel vessel and exploded.
- Which reagent can be used for the alkylation of aromatic nitro compounds
- At petrol pump, which rubber is used
- Which one will give positive iodoform test
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Primary,secondary and tertiary amines may be separated by using
- 10g of hydrogen and 64g of oxygen were filled in a steel vessel and exploded.
- Which reagent can be used for the alkylation of aromatic nitro compounds
- At petrol pump, which rubber is used
- Which one will give positive iodoform test
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply