| ⇦ | 
| ⇨ |
Oxidation numbers of P in PO₄³⁻, of S in SO₄²⁻ and that of Cr in Cr₂O₇²⁻ are respectively
Options
(a) 3,6 and 5
(b) 5,3 and 6
(c) -3, 6 and 6
(d) 5,6 and 6
Correct Answer:
5,6 and 6
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In the compounds KMnO₄ and K₂Cr₂O₇, the highest oxidation state is of the element
- The K(sp) of Ag₂CrO₄, AgCl,AgBr and AgI are respectively. 1.1 ˣ 10⁻¹²,1.8 ˣ 10⁻¹⁰,
- The equation ΔG = ΔH – TΔS is for
- Which of the following statements is correct regarding the drawbacks of raw rub
- The orthophosphoric acid is a
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the compounds KMnO₄ and K₂Cr₂O₇, the highest oxidation state is of the element
- The K(sp) of Ag₂CrO₄, AgCl,AgBr and AgI are respectively. 1.1 ˣ 10⁻¹²,1.8 ˣ 10⁻¹⁰,
- The equation ΔG = ΔH – TΔS is for
- Which of the following statements is correct regarding the drawbacks of raw rub
- The orthophosphoric acid is a
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply