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Oxidation number of chromium in Na₂Cr₂O₇ is
Options
(a) 2
(b) 4
(c) 3
(d) 6
Correct Answer:
6
Explanation:
Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.
Related Questions: - If ionization potential for hydrogen atom is 13.6eV, then ionization potential
- The weakest base among the following is
- Mg burns in CO₂ to produce
- When chloroform is exposed to light and air, it forms
- Molecular mass of a compound having empirical formula C₂H₅O is 90.
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If ionization potential for hydrogen atom is 13.6eV, then ionization potential
- The weakest base among the following is
- Mg burns in CO₂ to produce
- When chloroform is exposed to light and air, it forms
- Molecular mass of a compound having empirical formula C₂H₅O is 90.
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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