| ⇦ | 
| ⇨ |
Oxidation number of chromium in Na₂Cr₂O₇ is
Options
(a) 2
(b) 4
(c) 3
(d) 6
Correct Answer:
6
Explanation:
Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.
Related Questions: - An organic compound containing C, H and O gave the following analysis
- The number of moles of KMnO₄ reduced by one mole of KI in alkaline medium is
- Which of the following will not be soluble in sodium hydrogen carbonate
- An equation is given as:SnO₂ + C → Sn + CO.Its balanced form will involve
- Alkyl halides with metallic sodium in dry ether producing
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An organic compound containing C, H and O gave the following analysis
- The number of moles of KMnO₄ reduced by one mole of KI in alkaline medium is
- Which of the following will not be soluble in sodium hydrogen carbonate
- An equation is given as:SnO₂ + C → Sn + CO.Its balanced form will involve
- Alkyl halides with metallic sodium in dry ether producing
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply