Oxidation number of chromium in Na₂Cr₂O₇ is

Oxidation Number Of Chromium In Nacro Is Chemistry Question

Oxidation number of chromium in Na₂Cr₂O₇ is

Options

(a) 2
(b) 4
(c) 3
(d) 6

Correct Answer:

6

Explanation:

Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.

Related Questions:

  1. An organic compound containing C, H and O gave the following analysis
  2. The number of moles of KMnO₄ reduced by one mole of KI in alkaline medium is
  3. Which of the following will not be soluble in sodium hydrogen carbonate
  4. An equation is given as:SnO₂ + C → Sn + CO.Its balanced form will involve
  5. Alkyl halides with metallic sodium in dry ether producing

Topics: D and F Block Elements (91)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*