| ⇦ |
| ⇨ |
Oxidation number of chromium in Na₂Cr₂O₇ is
Options
(a) 2
(b) 4
(c) 3
(d) 6
Correct Answer:
6
Explanation:
Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.
Related Questions: - The geometry of Ni(CO)₄ and Ni(PPh₃)₂Cl₂ are
- Benzoic acid with Ba(OH)₂ gives
- In the periodic table from left to right in a period,the atomic volume
- The minimum amount of energy required for the reacting molecules to undergo
- Which one of the following statements for the order of a reaction is incorrect
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The geometry of Ni(CO)₄ and Ni(PPh₃)₂Cl₂ are
- Benzoic acid with Ba(OH)₂ gives
- In the periodic table from left to right in a period,the atomic volume
- The minimum amount of energy required for the reacting molecules to undergo
- Which one of the following statements for the order of a reaction is incorrect
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply