| ⇦ |
| ⇨ |
Oxidation number of chromium in Na₂Cr₂O₇ is
Options
(a) 2
(b) 4
(c) 3
(d) 6
Correct Answer:
6
Explanation:
Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.
Related Questions: - Two miscible liquids can be separated by
- In alkaline hydrolysis of a tertiary alkyl halides by aqueous alkali,
- Na₂CO₃ is manufactured by solvay process, the products that are recycled are
- Living in the atmosphere of CO is dangerous, because it
- The absolute enthalpy of neutralisation of the reaction
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two miscible liquids can be separated by
- In alkaline hydrolysis of a tertiary alkyl halides by aqueous alkali,
- Na₂CO₃ is manufactured by solvay process, the products that are recycled are
- Living in the atmosphere of CO is dangerous, because it
- The absolute enthalpy of neutralisation of the reaction
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply