| ⇦ | 
| ⇨ |
Oxidation number of chromium in Na₂Cr₂O₇ is
Options
(a) 2
(b) 4
(c) 3
(d) 6
Correct Answer:
6
Explanation:
Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.
Related Questions: - The momentum of a particle having a de Broglie wavelength of 10⁻¹⁷metres is
- Which of the following explains the sequence of filling the electrons
- Reaction between an acyl halide and the sodium salt of a fatty acid results in
- In which process,fused sodium hydroxide is eletrolysed for extraction of sodium
- Aluminium (III) chloride forms a dimer because aluminium
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The momentum of a particle having a de Broglie wavelength of 10⁻¹⁷metres is
- Which of the following explains the sequence of filling the electrons
- Reaction between an acyl halide and the sodium salt of a fatty acid results in
- In which process,fused sodium hydroxide is eletrolysed for extraction of sodium
- Aluminium (III) chloride forms a dimer because aluminium
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply