Oxidation number of chromium in Na₂Cr₂O₇ is

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Oxidation number of chromium in Na₂Cr₂O₇ is

Options

(a) 2
(b) 4
(c) 3
(d) 6

Correct Answer:

6

Explanation:

Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.

Related Questions:

1. A primary alcohol,C₃H₈O (A) on heating with sulphuric acid undergo dehydration
2. In H₂O₂ molecules, the angle between two O-H planes is
3. In the chemical reaction 2SO₂ + O₂ ⇌ 2SO₃, increasing the total pressure leads to
4. Which of the following undergoes sublimation
5. What is the pressure of 64g O₂ enclosed in a cylinder of 20 litres at 27⁰C

Topics: D and F Block Elements (91)
Subject: Chemistry (2512)

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