| ⇦ | 
| ⇨ |
Oxidation number of chromium in Na₂Cr₂O₇ is
Options
(a) 2
(b) 4
(c) 3
(d) 6
Correct Answer:
6
Explanation:
Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.
Related Questions: - The number of structural isomers possible from the molecular formula C₃H₉N is
- An aqueous solution of CoCl₂ on addition of excess of concentration HCl
- If α is dissociation constant, then the total number of moles for the reaction
- Cynanide and reacts isocyanide are isomers of type
- Of the following, which change will shift the reaction towards the product
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The number of structural isomers possible from the molecular formula C₃H₉N is
- An aqueous solution of CoCl₂ on addition of excess of concentration HCl
- If α is dissociation constant, then the total number of moles for the reaction
- Cynanide and reacts isocyanide are isomers of type
- Of the following, which change will shift the reaction towards the product
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply