| ⇦ | 
| ⇨ |
Oxidation number of chromium in Na₂Cr₂O₇ is
Options
(a) 2
(b) 4
(c) 3
(d) 6
Correct Answer:
6
Explanation:
Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.
Related Questions: - Square planar complex of the type MABXL(where A,B,X and L are unidentates) show
- The ratio of the difference in energy between first and second Bohr orbit
- What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl
- Which of the following is the IUPAC name of the compound
- Aufbau principle does not give the correct arrangement of filling up of atomic
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Square planar complex of the type MABXL(where A,B,X and L are unidentates) show
- The ratio of the difference in energy between first and second Bohr orbit
- What is the [OH⁻] in the final solution prepared by mixing 20 mL of 0.05 M Hcl
- Which of the following is the IUPAC name of the compound
- Aufbau principle does not give the correct arrangement of filling up of atomic
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply