| ⇦ | 
| ⇨ |
Oxidation number of chromium in Na₂Cr₂O₇ is
Options
(a) 2
(b) 4
(c) 3
(d) 6
Correct Answer:
6
Explanation:
Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.
Related Questions: - Dihedral angle in staggered form of ethane is
- Which electronic configuration of an element has abnormally high difference
- The ozone layer forms naturally by
- Nitrogen dioxide and sulphur dioxide have some properties in common.
- If r is the radius of the first orbit, the radius of nth-orbit of H-atom is given
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Dihedral angle in staggered form of ethane is
- Which electronic configuration of an element has abnormally high difference
- The ozone layer forms naturally by
- Nitrogen dioxide and sulphur dioxide have some properties in common.
- If r is the radius of the first orbit, the radius of nth-orbit of H-atom is given
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply