| ⇦ | 
| ⇨ |
Oxidation number of chromium in Na₂Cr₂O₇ is
Options
(a) 2
(b) 4
(c) 3
(d) 6
Correct Answer:
6
Explanation:
Oxidation number of chromium in Na₂Cr₂O₇ is +6. Oxidation number of Na = +1. Oxidation number of O = -2. Therefore 2 + 2x -2 * 7 = 0.⇒ 2x – 12 = 0 , ⇒ x = +6.
Related Questions: - Which of the following organic compounds polymerizes to form the polyester Dacron
- Which of the following statements is false
- Which ion is detected by Nessler’s reagent
- A 6 volume sample of H₂O₂
- Silver sulphide dissolves in a solution of sodium cyanide to form the complex
Topics: D and F Block Elements
(91)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following organic compounds polymerizes to form the polyester Dacron
- Which of the following statements is false
- Which ion is detected by Nessler’s reagent
- A 6 volume sample of H₂O₂
- Silver sulphide dissolves in a solution of sodium cyanide to form the complex
Topics: D and F Block Elements (91)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply