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On bombarding U²³⁵ by slow neutron, 200 MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be
Options
(a) 8×10¹⁶/s
(b) 20×10¹⁶/s
(c) 5×10²²/s
(d) 5×10¹⁶/s
Correct Answer:
5×10¹⁶/s
Explanation:
Energy released per fission of uranium = 200 × 10⁶ × 1 × 10⁻¹⁹ J
Power output = 1.6 × 10⁶ W
Number of fission /s = 1.6 × 10⁶ / 200 × 10⁶ × 1 × 10⁻¹⁹ = 5 × 10¹⁶ /s
This is the rate of fission.
Related Questions: - A spherical body of emissivity e=0.6, placed inside a perfectly black body is maintained
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- A string in musical instrument is 50 cm long and its fundamental frequency is 800 Hz.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spherical body of emissivity e=0.6, placed inside a perfectly black body is maintained
- A point charge q is situated at a distance r on axis from one end of a thin
- A string in musical instrument is 50 cm long and its fundamental frequency is 800 Hz.
- In which of the following systems will the radius of the first orbit (n=1) be minimum?
- Magnetic induction produced at the centre of a circular loop carrying current is B.
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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