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Number of moles of MnO₄⁻ required to oxidize one mole of ferrous oxalate completely in acidic medium will be
Options
(a) 0.6 moles
(b) 0.4 moles
(c) 7.5 moles
(d) 0.2 moles
Correct Answer:
0.6 moles
Explanation:
10FeC2O4 + 6KMnO4 + 24H2SO4 —-> 3K2SO4+ 6MnSO4 + 5Fe2(SO4)3 + 24H2O + 20CO2
From the above balanced equation, we observe that
6 moles of KMnO4 is required to oxidize 10 moles of FeC2O4
Then, 1 mole of FeC2O4 would be oxidized by = 6/10=0.6
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