| ⇦ | 
| ⇨ |
Number of moles of MnO₄⁻ required to oxidize one mole of ferrous oxalate completely in acidic medium will be
Options
(a) 0.6 moles
(b) 0.4 moles
(c) 7.5 moles
(d) 0.2 moles
Correct Answer:
0.6 moles
Explanation:
10FeC2O4 + 6KMnO4 + 24H2SO4 —-> 3K2SO4+ 6MnSO4 + 5Fe2(SO4)3 + 24H2O + 20CO2
From the above balanced equation, we observe that
6 moles of KMnO4 is required to oxidize 10 moles of FeC2O4
Then, 1 mole of FeC2O4 would be oxidized by = 6/10=0.6
Related Questions: - The process which is catalysed by one of the products is called
- When enthalpy and entropy change for a chemical reaction are – 2.5 x 10³ cals
- The solubility product of a sparingly soluble salt AB at room temperature
- In which of the following, the entropy decreases
- The solubility of saturated solution of calcium fluoride is 2 ˣ 10⁻⁴ moles
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The process which is catalysed by one of the products is called
- When enthalpy and entropy change for a chemical reaction are – 2.5 x 10³ cals
- The solubility product of a sparingly soluble salt AB at room temperature
- In which of the following, the entropy decreases
- The solubility of saturated solution of calcium fluoride is 2 ˣ 10⁻⁴ moles
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply