| ⇦ | 
| ⇨ |
Moment of inertia, along the diameter of a ring is
Options
(a) 3MR² / 2
(b) MR² / 2
(c) MR²
(d) 2MR²
Correct Answer:
MR² / 2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The numebr 0 (zero) is required for
- For a satellite escape velocity is 11 kms⁻¹.If the satellite is launched at an angle
- A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface
- Identify the wrong statement with reference to solar cell
- The displacement of a particle varies according to the relation x=4 (cos π t + sin π t)
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The numebr 0 (zero) is required for
- For a satellite escape velocity is 11 kms⁻¹.If the satellite is launched at an angle
- A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface
- Identify the wrong statement with reference to solar cell
- The displacement of a particle varies according to the relation x=4 (cos π t + sin π t)
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply