| ⇦ | 
| ⇨ |
MnO₄²⁻ (1 mole) in neutral aqueous medium is disproportionated to
Options
(a) 2/3 mole of MnO₄⁻ and 1/3 mole of MnO₂
(b) 1/3 mole of MnO₄⁻ and 2/3 mole of MnO₂
(c) 1/3 mole of Mn₂O₇ and 1/3 mole of MnO₂
(d) 2/3 mole of Mn₂O₇ and 1/3 mole of MnO₂
Correct Answer:
2/3 mole of MnO₄⁻ and 1/3 mole of MnO₂
Explanation:
3MnO₄⁻² + 2H₂O →MnO₂(s) + 2MnO₄⁻ +4OH⁻
for one mole
MnO₄⁻² +2/3 H₂O →1/3 MnO₂(s) + 2/3 MnO₄⁻ + 4/3 OH⁻.
Related Questions: - At 298 K the enthalpy of formation of liquid water is -285.9 kJ/mol
- Heat of formation of H₂O(g) at 25⁰C is -243 kJ,ΔE for the reaction
- The diagonal partner of element B is
- What is the molar ratio of mixture of gases given the ratio of gases
- Boron is unable to form BF₆³⁻ because of
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At 298 K the enthalpy of formation of liquid water is -285.9 kJ/mol
- Heat of formation of H₂O(g) at 25⁰C is -243 kJ,ΔE for the reaction
- The diagonal partner of element B is
- What is the molar ratio of mixture of gases given the ratio of gases
- Boron is unable to form BF₆³⁻ because of
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply