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Maximum velocity of the photoelectrons emitted by a metal surface is 1.2×10⁶ ms⁻¹. Assuming the specific charge of the electron to be 1.8×10¹¹ C kg⁻¹, the value of the stopping potential in volt will be
Options
(a) 2
(b) 3
(c) 4
(d) 6
Correct Answer:
4
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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- The electric potential V at any point (x,y,z) all in meters in space is given by
- The value of n so that vectors 2i+3j-2k, 5i+nj+k and -i+2j+3k may be coplanar,will be
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- A beam of light contains two wavelengths 6500Å and 5200Å.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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ev=(1/2)mV^2max
v= (mV^2max)/2e
=(V^2max)/2 (e/m)
=((1.2×10^6)^2)/(2×1.8×10^11)=4v