⇦ | ⇨ |
Maximum velocity of the photoelectrons emitted by a metal surface is 1.2×10⁶ ms⁻¹. Assuming the specific charge of the electron to be 1.8×10¹¹ C kg⁻¹, the value of the stopping potential in volt will be
Options
(a) 2
(b) 3
(c) 4
(d) 6
Correct Answer:
4
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The motion of a particle along a straight line is described by equation
- A projectile is fired at an angle of 45° with the horizontal
- A body of mass 120 kg and density 600 kg/m³ floats in water.
- For a wave propagating in a medium, identify the property that is independent
- A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The motion of a particle along a straight line is described by equation
- A projectile is fired at an angle of 45° with the horizontal
- A body of mass 120 kg and density 600 kg/m³ floats in water.
- For a wave propagating in a medium, identify the property that is independent
- A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
ev=(1/2)mV^2max
v= (mV^2max)/2e
=(V^2max)/2 (e/m)
=((1.2×10^6)^2)/(2×1.8×10^11)=4v