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Maximum velocity of the photoelectrons emitted by a metal surface is 1.2×10⁶ ms⁻¹. Assuming the specific charge of the electron to be 1.8×10¹¹ C kg⁻¹, the value of the stopping potential in volt will be
Options
(a) 2
(b) 3
(c) 4
(d) 6
Correct Answer:
4
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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(150)
Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into
- The moment of inertia of a thin circular disc about an axis passing through its centre
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- The threshold wavelength for photoelectric emission from a material is 4800 Å.
- Light of wavelength 500 nm is incident on a metal with work function 2.28 eV.
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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ev=(1/2)mV^2max
v= (mV^2max)/2e
=(V^2max)/2 (e/m)
=((1.2×10^6)^2)/(2×1.8×10^11)=4v