⇦ | ⇨ |
Maximum velocity of the photoelectrons emitted by a metal surface is 1.2×10⁶ ms⁻¹. Assuming the specific charge of the electron to be 1.8×10¹¹ C kg⁻¹, the value of the stopping potential in volt will be
Options
(a) 2
(b) 3
(c) 4
(d) 6
Correct Answer:
4
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A moving neutron collides with a stationary α-particle.The fraction of the kinetic energy
- During mean life of a radioactive element, the fraction that disintegrates is
- A particle is executing SHM along a straight line. Its velocities at distances
- Two coherent sources of intensity ratio α interfere. In interference pattern,
- A roller coaster is designed such that riders experience “weightlessness” as they
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A moving neutron collides with a stationary α-particle.The fraction of the kinetic energy
- During mean life of a radioactive element, the fraction that disintegrates is
- A particle is executing SHM along a straight line. Its velocities at distances
- Two coherent sources of intensity ratio α interfere. In interference pattern,
- A roller coaster is designed such that riders experience “weightlessness” as they
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
ev=(1/2)mV^2max
v= (mV^2max)/2e
=(V^2max)/2 (e/m)
=((1.2×10^6)^2)/(2×1.8×10^11)=4v