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Masses of 3 wires of same metal are in the ratio 1:2:3 and their lengths are in the ratio 3:2:1. The electric resistances are in the ratio
Options
(a) (1:4:9)
(b) (9:4:1)
(c) (1:2:3)
(d) (27:6:1)
Correct Answer:
(27:6:1)
Explanation:
Mass = volume × density = A.l.d
Ald = m
Resistance R = ρl / A = ρl / (m/ld) = dρ (l²/m)
Now, R₂ / R₁ = (ρd / ρd) )(l₂² / l₁²) (m₁/m₂)
= (2/3)² × (1/2) = 2 / 9
⇒ R₂ = (2 / 9) R₁
Again R₃ / R₁ = (ρd / ρd) )(l₃² / l₁²) (m₁/m₃)
= (1/3)² × (1/3) = 1 / 27
⇒ R₃ = (R₁ / 27)
.·. R₁ : R₂ : R₃ = R₁ : (2/9) R₁ : (R₁/27) = 27 : 6 : 1
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Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Wheatstone bridge, three resistors P,Q and R are conncected in three arms
- The dimensions of universal gas constant are
- Two beams of light having intensities I and 4I interfere to produce a fringe pattern
- In a radioactive decay process, the negatively charged emitted β- particles are
- If a steel wire of length l and magnetic moment M is bent into a semicircular arc,
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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