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20.0 g of a magnesium carbonate sample decomposes on heating to give CO₂ and 8.0 g magnesium oxide. What will be the percentage purity of magnesium carbonate in the sample?
Options
(a) 75
(b) 96
(c) 60
(d) 84
Correct Answer:
84
Explanation:
MgCO₃ -> MgO + CO₂
84 g of MgCO₃ form 40 g of MgO
20g of MgCO₃ form (40 * 20) / 84 g of MgO
= 9.52 g of MgO
Since 8 g of MgO is formed, purity = (8 / 9.52) *100 = 84%
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Question Type: Apply
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Difficulty Level: Moderate
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- NaOCl is used as a bleaching agent and sterilising agent. It can be synthesized
- Artificial sweetner which is stable under cold conditions only is
- The weight of silver (at.wt. = 108) displaced by a quantity of electricity
- The molecular of CO₂ has angle 180°.It can be explained on the basis of
- How many moles of iodine are liberated when 1 mole of potassium dichromate
Question Type: Apply (15)
Difficulty Level: Moderate (4)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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